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A man of mass 60 kg is standing on a boa...

A man of mass 60 kg is standing on a boat of mass 140 kg, which is at rest in still water. The man is initially at 20 m from the shore. He starts walking on the boat for 4 s with constant speed 1.5 m/s towards the shore. The final distance of the man from the shore is

A

15.8 m

B

4.2 m

C

12.6 m

D

14.1 m

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to analyze the situation involving the man and the boat. ### Step 1: Understand the Initial Setup - The man has a mass of 60 kg and is standing on a boat with a mass of 140 kg. - Initially, both the man and the boat are at rest, and the man is 20 meters away from the shore. **Hint:** Identify the masses and the initial distance from the shore. ### Step 2: Calculate the Distance the Man Walks - The man walks towards the shore with a constant speed of 1.5 m/s for 4 seconds. - Distance walked by the man = speed × time = 1.5 m/s × 4 s = 6 meters. **Hint:** Use the formula for distance: Distance = Speed × Time. ### Step 3: Determine the Boat's Movement - When the man walks towards the shore, the boat will move in the opposite direction due to conservation of momentum. - The relative displacement of the boat can be calculated using the formula: \[ \text{Displacement of boat} = \frac{m_{\text{man}} \times d_{\text{man}}}{m_{\text{boat}} + m_{\text{man}}} \] where: - \( m_{\text{man}} = 60 \, \text{kg} \) - \( d_{\text{man}} = 6 \, \text{m} \) (distance walked by the man) - \( m_{\text{boat}} = 140 \, \text{kg} \) - Substituting the values: \[ \text{Displacement of boat} = \frac{60 \, \text{kg} \times 6 \, \text{m}}{140 \, \text{kg} + 60 \, \text{kg}} = \frac{360}{200} = 1.8 \, \text{m} \] **Hint:** Remember to apply conservation of momentum when one object moves. ### Step 4: Calculate the Final Position of the Man - The final distance of the man from the shore is given by: \[ \text{Final distance from shore} = \text{Initial distance from shore} - \text{Distance walked by man} + \text{Displacement of boat} \] - Substituting the values: \[ \text{Final distance from shore} = 20 \, \text{m} - 6 \, \text{m} + 1.8 \, \text{m} = 15.8 \, \text{m} \] **Hint:** Keep track of the directions while calculating the final position. ### Conclusion The final distance of the man from the shore is **15.8 meters**. **Final Answer:** 15.8 m (Option 1)
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