Home
Class 12
PHYSICS
A disc has mass 9 m. A hole of radius R/...

A disc has mass 9 m. A hole of radius R/3 is cut from it as shown in the figure. The moment of inertia of remaining part about an axis passing through the centre 'O' of the disc and perpendicular to the plane of the disc is :

A

`(32)/(9)MR^(2)`

B

`10 MR^(2)`

C

`(40)/(9)MR^(2)`

D

`4 MR^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

A circular of radius R has mass 9m . A hole of radius (R)/(3) is cut from it as shown in figure. The moment of inertia of the remaining part about an axis passing through centre 0 of the disc and perpendicular of the plane of disc is xmR^(2) .Find value of x

Calculate the moment of inertia of a disc of radius R and mass M, about an axis passing through its centre and perpendicular to the plane.

The moment of inertia of a circular disc about an axis passing through the circumstances perpendicular to the plane of the disc is

If a circular concentric hole is made on a disc then about an axis passing through the centre of the disc and perpendicular to its plane

The moment of inertia of a copper disc, rotating about an axis passing through its centre and perpendicular to its plane

A circular hole of radius r//2 is cut from a circular disc of radius 'r' . The disc lies in the xy plane. Determine the moment of inertia about an axis passing through the centre and perpendicular to the plane of the disc.

A uniform disc having radius 2R and mass density sigma as shown in figure. If a small disc of radius R is cut from the disc as shown. Then find out the moment of inertia of remaining disc around the axis that passes through O and is perpendicular to the plane of the page.