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(3x-2iy)(2+i)^(2)=10(1+i)...

(3x-2iy)(2+i)^(2)=10(1+i)

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Find the values of x and y : (i) x+3i=6-9iy (ii) (x+iy)-(3-2i)=5+i (iii) i=x+2yi (iv) 4x+i(x-y)=2-5i (v) (x+2iy)(2-i)^(2)=10(1-i)

Find the values of x and y : (i) x+3i=6-9iy (ii) (x+iy)-(3-2i)=5+i (iii) i=x+2yi (iv) 4x+i(x-y)=2-5i (v) (x+2iy)(2-i)^(2)=10(1-i)

Write the following in the form x + iy : ((3- 2i) (2+ 3i))/((1 + 2i) (2-i)) .

((x+iy)/(2+3i)+(2+i)/(2-3i)=(9)/(13)(1+i)

(x+iy)(2-3i)=4+i

If ((1+i)/(1-i))^(2) - ((1-i)/(1+i))^(2) = x + iy then find (x,y).

If ((1+i)/(1-i))^(2) - ((1-i)/(1+i))^(2) = x + iy then find (x,y).

IF the conjugate of ( x+ iy)(1-2i) is (1 +i) then

Find the real values of x and y for which : {:((i),(1-i)x+(1+i)y=1 - 3i,(ii),(x+iy)(3-2i)=(12+5i)),((iii),x+4yi =ix + y + 3,(iv),(1+i)y^(2)+(6+i)=(2+i)x),((v),((x+3i))/((2+iy))=(1-i),(vi),((1+i)x-2i)/((3+i))+((2-3i)y+i)/((3-i))=i):}