[" 牙 "x=y cos(2 pi)/(3)=tau*cos(4 pi)/(3)" Then "xy+y_(z+2x)],[A=0]

If x=y cos((2 pi)/(3))=z cos((4 pi)/(3)), then xy+yz+zx=

If x=y cos((2pi)/(3))=z cos ((4pi)/(3)) then xy+yz+zx=

If x=y cos backslash(2 pi)/(3)=z cos backslash(4 pi)/(3), then xy+yz+zx is equal to

If x*cos theta=y*cos(theta+(2 pi)/(3))=2*cos(theta+(4 pi)/(3)) then evaluate xy+yz+zx

If x cos theta=y cos(theta+(2 pi)/(3))=z cos(theta+(4 pi)/(3)), prove that xy+yz+zx=0

If x costheta=y cos (theta+(2pi)/3)=z cos(theta+(4pi)/3) show that xy + yz+ zx = 0

If x cos theta=y cos(theta+(2 pi)/(3))=z cos(theta+(4 pi)/(3)), then write the value of (1)/(x)+(1)/(y)=(1)/(z)