`tany*(dy)/(dx)+tanx=cosycos^2x`

(dy)/(dx)+2tanx=0

(dy)/(dx)tany=sinx+cosx

(dy)/(dx)tany=sin(x+y)+sin(x-y)

The solution of the differential equation (dy)/(dx)-(tany)/(x)=(tanysiny)/(x^(2)) , is

The solution of the differential equation (dy)/(dx)-(tany)/(x)=(tanysiny)/(x^(2)) , is

(tany)(dy)/(dx)=sin(x+y)-sin(x-y) A) secy tany = 2 sin x+c B) log(cosy-coty)=2sin x+c C) log(secy+tany)=2sin x+c D) secy+tany=c.e^(sinx)

Find dy/dx if tany=x+y