`y(dy)/(dx)sinx=cosx(sinx-(y^2)/2);` where at `x=pi/2,`

y(dy)/(dx)sinx=cosx(sinx-(y^(2))/(2)),y=1" when "x=(pi)/(2)

ysinx dy/dx=(sinx-y^2)cosx

ysinx dy/dx=(sinx-y^2)cosx

If y= (sinx + cosx)/(sinx - cosx) then (dy)/(dx) at x = pi/2 is …………………….. .

If y=(sinx-cosx)^((sinx-cosx)) where (pi)/(4)ltxlt(3pi)/(4) , then find (dy)/(dx) .

If y=((log)_(cosx)sinx)((log)_(sinx)cosx)+sin^(-1)(2x)/(1+x^2) , then (dy)/(dx) at x=pi/2 is equal to.......

If y=(sinx+cosx)/(sinx-cosx) , then (dy)/(dx)" at "x=0 is