`y=tan^(-1)((acosx-bsinx)/(bcosx+asinx)), `where `-pi/2ltxltpi`and `a/btanx gt -1`

tan^(-1)((a+bcosx)/(b-acosx))

(d)/(dx)[tan^(-1)((asinx+bcosx)/(acosx-bsinx))]=

Find the differentiation of y=tan^(-1)((acosx-bsinx)/(bcosx+asinx))

Differentiate the following functions with respect to x : (i) tan^(-1)((a+x)/(1-a x)) (ii) tan^(-1)((acosx-bsinx)/(bcosx+asinx)), -pi/2 -1

If (a)/(b)tanxgt-1,"then "tan^(-1)[(acosx-bsinx)/(bcosx+asinx)] is

If y=tan^(-1)sqrt(((1+sinx)/(1-sinx))),(pi)/(2)ltxltpi, then (dy)/(dx) equals to

The value of cot^(-1){(sqrt(1-sinx)+sqrt(1+sinx))/(sqrt(1-sinx)-sqrt(1+sinx))} , where (pi)/2ltxltpi , is

What is (dsqrt(1-sin2x))/dx equal to, where pi/4ltxltpi/2 ?

If y=sin^(-1)[(acosx+bsinx)/(sqrt(a^(2)+b^(2)))]," then "(dy)/(dx)=