Home
Class 12
MATHS
Sketch the region {(x, 0):y=sqrt(4-x^(2)...

Sketch the region `{(x, 0):y=sqrt(4-x^(2))}` and X-axis. Find the area of the region using integration.

Text Solution

Verified by Experts

The correct Answer is:
N/a

Given region is `{(x, 0):y=sqrt(4-x^(2))}` and X-axis.
We have, `y=sqrt(4-x^(2))rArry^(2)=4-x^(2)rArrx^(2)+y^(2)=4`

`:." Area of shaded region, "A=int_(-2)^(2)sqrt(4-x^(2))dx=int_(-2)^(2)sqrt(2^(2)-x^(2))dx`
`=[x/2sqrt(2^(2)-x^(2))+(2^(2))/2 .sin^(-1)(x)/2]_(-2)^(2)`
`=2/2 .0+0. pi/2+2/2 .0-2sin^(-1)(-1)=2. pi/2+2. pi/2`
`=2pi" sq units"`
Promotional Banner

Topper's Solved these Questions

  • APPLICATION OF DERIVATIVES

    NCERT EXEMPLAR|Exercise Application Of Derivatives|64 Videos
  • CONTINUITY AND DIFFERENTIABILITY

    NCERT EXEMPLAR|Exercise Continuity And Differentiability|212 Videos

Similar Questions

Explore conceptually related problems

Sketch the region lying in the first quadrant and bouded by y=1 and y=4. Find the y=9x^(2),x=0,y=1 and y=4. Find the area of the region using integration.

Sketch the region common to the cirvle x^2+y^2=25 and the parabola y^2=8x Also find the area of the region using intergration .

Sketch the region common to the circle x^2 +y^2=16 and the parabola x^2=6y Also find the area of the region using intergration

Sketch the region lying in the first quadrant and bounded by y = 4x^2 ,x = 0, y = 2 and y = 4. Find the area of the region using integration.

Sketch the region {(x,y): 4x ^(2) + 9y ^(2) = 36} and find its area, using integration.

Draw a rough sketch of the following region and find the area enclosed by the region, using method of integration : {(x,y): y ^(2) le 5x, 5x ^(2) + 5y ^(2)le 36}.

Draw a rough sketch of the region {(x,y) : y^(2)le 6 a x and x^(2)+y^(2)le 16 a^(2)} . Also, find the area of the region sketched using method of integration.

Sketch the region bounded by the curves y=sqrt(5-x^(2)) and y=|x-1| and find its area.

Sketch the graph of y=sqrt(x)+1 "in"[0,4] and determine the area of the region enclosed by the curve, the axis of X and the lines x=0,x=4 .

Draw a rough sketch of the given curve y=1+abs(x+1),x=-3, x-=3, y=0 and find the area of the region bounded by them, using integration.

NCERT EXEMPLAR-APPLICATION OF INTEGRALS-Application Of Integrals
  1. Find the area of the region enclosed by the parabola x^(2)=y and the l...

    Text Solution

    |

  2. Find the area of the region bounded by line x = 2 and parabola y^(2)=8...

    Text Solution

    |

  3. Sketch the region {(x, 0):y=sqrt(4-x^(2))} and X-axis. Find the area o...

    Text Solution

    |

  4. Calculate the area under the curve y=2sqrtx included between the lines...

    Text Solution

    |

  5. Using integration, find the area of the region bounded by the line 2y=...

    Text Solution

    |

  6. Draw a rough sketch of the curve y=sqrtx-1) in the interval [1, 5]. Fi...

    Text Solution

    |

  7. Determine the area under the curve y=sqrt(a^(2)-x^(2)) included betwee...

    Text Solution

    |

  8. Find the area if the region bounded by y=sqrtx" and " y=x.

    Text Solution

    |

  9. Find the area enclosed by the curve y=-x^(2) and the straight line x+y...

    Text Solution

    |

  10. Find the area bounded by the curve y=sqrtx,x=2y+3 in the first quadran...

    Text Solution

    |

  11. Find the area of the region bounded by the curve y^(2)=2x" and "x^(2)+...

    Text Solution

    |

  12. Find the area of region by the curve y=sinx" between "x=0" and "x=2pi.

    Text Solution

    |

  13. Using integration, find the area of the triangle ABC whose vertices ar...

    Text Solution

    |

  14. Find the area of the region {(x, y) : y^2 <=6ax and x^2+y^2<=16a^2} ...

    Text Solution

    |

  15. Compute the area bounded by the lines x +2y=2,y-x=1" and " 2x+y=7.

    Text Solution

    |

  16. Find the area bounded by the lines y=4x+5, y=5-x" and "4y=x+5.

    Text Solution

    |

  17. Find the area bounded by the curve y=2 cosx and the X-axis from x = ...

    Text Solution

    |

  18. Draw a rough sketch of the given curve y=1+abs(x+1),x=-3, x-=3, y=0 an...

    Text Solution

    |

  19. The area of the region bounded by the Y-"axis", y = "cos" x and y = "s...

    Text Solution

    |

  20. The area of the region bounded by the curve x^(2)=4y and the straight ...

    Text Solution

    |