`ABCD` एक चतुर्भुज है और AC और BD इसके विकर्ण हैं । सिद्ध करो कि सदिश `vec(AB)+vec(DC)=vec(AC)+vec(DB)`

In a quadrilateral ABCD, vec(AB) + vec(DC) =

In a quadrilateral ABCD, vec(AB) + vec(DC) =

ABCD is a parallelogram and AC, BD are its diagonals. Show that : vec(AC)+vec(BD)=2vec(BC),vec(AC)-vec(BD)=2vec(AB) .

ABCD is a parallelogram and AC, BD are its diagonals. Show that : vec(AC)+vec(BD)=2vec(BC), vec(AC)-vec(BD)=2vec(AB) .

If ABCD is a parallelogram then vec(AB) + vec(AD) + vec(CB) + vec(CD) = …………………… .

If A, B, C and D aare four points and vec AB = vec DC then vec AC + vec BD =

vec(AC) and vec(BD) are the diagonals of a parallelogram ABCD. Prove that (i) vec(AC) + vec(BD) - 2 vec(BC) (ii) vec(AC) - vec(BD) - 2vec(AB)

ABCD is a parallelogram Fig. 2 (c ) .64. AC and (BD) are its diagonals. Show that (a) vec (AC) +vec (BD) =2 vec (BC) (b) vec (AC) - vec (BD) =2 vec (AB) .

In a parallelogram ABCD. Prove that vec(AC)+ vec (BD) = 2 vec(BC)