Area of the region bounded by the curve `y = "cos" x` between `x = 0` and `x = pi` is

Options

A. `2" sq units"`
B. `4" sq units"`
C. `3" sq units"`
D. `1" sq unit"`

Answer

A

Explanation

Required area enclosed by the curve `y=cosx, x=0" and " x=pi` is

`A=int_(0)^(pi//2)cosx dx +abs(int_(pi//2)^(pi)cosxdx)
`=[sin.pi/2-sin0]+abs(sin.pi/2-sinpi)`
`=1+1=2" sq units"`