Using contrapositive method prove that, if `n^(2)` is an even integer , then n is also an even integer.

Answer

N/a

Explanation

Let `p: n^(2)` an even integer.
q: n is also an even integer.
Let ~p is ture i.e., n is not an even integer.
`rArr n^(2) ` is not an even integer.`" "["since, square of an odd integer is odd"]`
`rArr ~ p` is ture.
Therefore, ~q is ture `rArr ~p` is true.