`y=tan^(-1)(x/(1+sqrt(1-x^2)))`

Differentaite w.r.t x , y = tan^(-1) (x /(sqrt(1+x^(2))-1))

If y=tan^(-1)((x)/(sqrt(1+x^(2))-1)), then (dy)/(dx)=

If y=tan^(-1)[(x-sqrt(1-x^(2)))/(x+sqrt(1-x^(2)))]," then "(dy)/(dx)=

Solve y=tan^(-1)((sqrt(1+x^(2))-1)/(x))

Let y_1=tan^(-1)((sqrt(1+x^2)-1)/x) and y_2=tan^(-1)((2xsqrt(1-x^2))/(1-2x^2)) then (dy_1)/(dy_2)=

Which of the following pairs of function/functions has same graph? y=tan(cos^(-1)x);y=(sqrt(1-x^(2)))/(x)y=tan(cot^(-1)x);y=(1)/(x)y=sin(tan^(-1)x);y=(x)/(sqrt(1-x^(2)))y=cos(tan^(-1)x);y=sin(cot^(-1)x)

If y=tan^(-1)((sqrt(1+x^(2))-1)/(x)) , then find (dy)/(dx) when -1lexle1.

Find the domain of the following: y=tan^(-1)(sqrt(x^(2)-1))

(tan^(-1)x)/(sqrt(1-x^(2))) withrespectto sin ^(-1)(2x sqrt(1-x^(2)))