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From the following table, calculate the ...

From the following table, calculate the coefficient of correlation by Karl Pearson's method:

Arithmetic means of X and Y series are 6 and 8 respectively.

Text Solution

Verified by Experts

Let us first and missing value of Y and let us denote it by a .
`bar(Y)=(sumY)/(N)=(9+11+a+8+7)/(5)=(35+a)/(5)`
`implies 8=(35+a)/(5)`
`:. 35+a=40`
`implies a=5`
Thus, the complete series is :

Now we find the coefficient of correlation.

`r=(sumxy)/(sqrt(sumx^(2)xxsumy^(2)))`
The table shows that ` sumxy=-26,sum x^(2)=40,sumy^(2)=20`
Substituting the values, we get
`r=(-26)/(sqrt(10xx20))`
`=(-26)/(sqrt(800))=(-26)/(28.28)`
`=-0.92`
Coefficient of Correlation (r)= -0.92
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