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If r=0.997,sumxy=46,bar(X)=4,bar(Y)=8,su...

If `r=0.997,sumxy=46,bar(X)=4,bar(Y)=8,sumx^(2)=28`, what will be the value of `sumy^(2)`?

Text Solution

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`r=(sumxy)/(sqrt(sumx^(2)xxsumy^(2)))`
Given : `r=0.997, sum xyl =46 , bar (X)=4, bar (Y)=8, sum x^(2)=28`
Substituting the values, we get
`0.997=(46)/(sqrt(28xx sumy^(2)))`
Squaring both side , we get
`0.994=(2,116)/(28xxsumy^(2))`
`implies 27.832xx sumy^(2)=2,116`
`sumy^(2)=76.03`
Value of `sumy^(2)=76.03`
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