Find `c` of `L M V T` `f(x)=\ sqrt(x-1)\ \ " in "\ [1,3]`

Find the domain of f(x) = sqrt(x-1) .

Verify L.M.V. theorem for f(x)=x(x-2)" on "[1,3]

" 1.Find the domain and range of "f(x)=sqrt(x-3)

(c) Find the domain of f(x)=sqrt((x)/(x-3)) .

Using Lagrange's theorem , find the value of c for the following functions : (i) x^(3) - 3x^(2) + 2x in the interval [0,1/2]. (ii) f(x) = 2x^(2) - 10x + 1 in the interval [2,7]. (iii) f(x) = (x-4) (x-6) in the interval [4,10]. (iv) f(x) = sqrt(x-1) in the interval [1,3]. (v) f(x) = 2x^(2) + 3x + 4 in the interval [1,2].

If f(x) = sqrt ((sec x -1)/(sec x + 1)) , find f'( pi /3)

Find the range of f(x)sqrt(x-1)+sqrt(5-x)

If mean value theorem holds good for the function f(x)=(x-1)/(x) on the interval [1,3] then the value of 'c' is 2 (b) (1)/(sqrt(3))( c) (2)/(sqrt(3))(d)sqrt(3)

Find F'(x) if (F(x)=sqrt(x^(2)+1))