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Consider function f(x)={x{x}+1,\ \ \...

Consider function `f(x)={x{x}+1,\ \ \ \ \ \ \ \ \ \ \ \ 0lt=x<1 2-{x},\ \ \ \ 1lt=xlt=2\ \ \ ` where `{x}:` fractional part function of `x` . Statement-1: Rolles Theorem is not applicable to `f(x)` in `[0,2]` Statement-2: `f(0)\ !=f(2)`

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