How many protons, electrons and neutrons are present in 0.18 g `._(15)^(20)P`?

Explanation

No of protons in one atom of P
=No. of protons in one atom of P=15
No. of neutrons in one atom of `P=(A-Z)`
`=(30-15)=15`
`0.18g ._(15)^(30)P=(0.18)/(30)=0.006` mol
No. of atoms in 0.006 mol=0.006`xx6.02xx10^(23)`
No. of protons in 0.006 mol `._(15)^(20)P=15xx0.006xx6.02xx10^(23)`
`=5.418xx10^(22)`.
So, No, of electrons `=5.418xx10^(22)`

and No. of neutrons `=5.418xx10^(22)`