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A blube emits light of lambda = 4500 Å. ...

A blube emits light of `lambda = 4500 Å`. The bulb is rated as 150 watt and `8%` of the energy is emitted as light. Number of photons emitted by bulb per second is : `["Take" hc = 12400 eVÅ]`

Text Solution

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Energy emitted per second by the bulb
`=150xx(8)/(100)J`
Energy of 1 photon `=(hc)/(lamda)=(6.626xx10^(-34)xx3xx10^(8))/(4500xx10^(-10))`
Let n photons be evolved per second.
`thereforenxx4.42xx10^(-19)=150xx(8)/(100)`
`n=27.2xx10^(18)`
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