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The maximum kinetic energy of the photoe...

The maximum kinetic energy of the photoelectrons is found to be `6.63xx10^(-19)J`, when the metal is irradiated with a radiation of frequency `2xx10^(15)`Hz. The threshold frequency of the metal is about:

A

`1xx10^(15)s^(-1)`

B

`2xx10^(15)s^(-1)`

C

`3xx10^(15)s^(-1)`

D

`1.5xx10^(15)s^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`KE=h(v-v_(0))`
`v_(0)=v-(KE)/(h)=2xx10^(15)-(6.63xx10^(-19))/(6.63xx10^(-34))=1xx10^(15)s^(-1)`.
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