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The energy difference between two electr...

The energy difference between two electronic states is `46.12 "kcal"//"mol"`. What will be the freqency of the light emitted when an electron drops from the higher to the lower energy state ? (Planck' constant `= 9.52 xx 10^-14 kcal sec mol^-1`)

Text Solution

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`Delta=46.12" kcal "mol^-1`
According to Bohr theory, `DeltaE=Nhv`
or `v=(DeltaE)/(Nh)=(46.12)/(9.52xx10^(-14))`
`=4.84xx10^(14)" cycle "sec^(-1)`.
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