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How many times does the electron go roun...

How many times does the electron go round the first Bohr's orbit of hydrogen in one second ?

Text Solution

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Number of revolution per second `=(v)/(2pir)` . . . (i)
`v=(2.188xx10^(8))/(n)cm//sec`
`v=(2.188xx10^(8))/(1)=2.188xx10^(8)cm//sec`
`r=(n^(2))/(Z)=xx0.529`Ã…
`=(1^(2))/(1)xx0.529xx10^(-8)cm`
`=0.529xx10^(-8)cm`
`therefore` Number of revolutions per sec `=(2.188xx10^(8))/(2xx3.14xx0.529xx10^(-8))`
`=6.59xx10^(15)`.
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