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Calculate the angular frequency of revol...

Calculate the angular frequency of revolution of an electron occupying the second Bohr orbit of `He^(+)` ion.

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Velocity of electron `(v)=(2piZe^(2))/(nh)` . . . (i)
Radius of `He^(+)` ion in an orbit `(r_(n))=(n^(2)h^(2))/(4pi^(2)mZe^(2))` . . .(ii)
Angular frequency or angular velocity `(omega)`
`=(v)/(r_(n))=(2piZe^(2))/(nh)xx(4pi^(2)mZe^(2))/(n^(2)h^(2))=(8pi^(3)mZ^(2)e^(4))/(n^(3)h^(3))`
Given, `n=2,m=9.1xx10^(-28)g,Z=2,e=4.8xx10^(-10)esu`
`h=6.626xx10^(-27)erg-sec`
`thereforeomega=(8xx((22)/(7))^(3)xx2^(2)xx9.1xx10^(-28)xx(4.8xx10^(-10))^(4))/((2)^(3)(6.626xx10^(-27))^(3))`
`=2.067xx10^(16)sec^(-1)`.
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