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The de Broglie wavelenth of 1 mg grain o...

The de Broglie wavelenth of `1 mg` grain of sand blown by a `20 m s^-1` wind is :

A

`3.3xx10^(-29)m`

B

`3.3xx10^(-21)m`

C

`3.3xx10^(-49)m`

D

`3.3xx10^(-42)m`

Text Solution

Verified by Experts

The correct Answer is:
A
`lamda=(h)/(mv)=(6.626xx10^(-34))/(1xx10^(-6)xx20)=3.313xx10^(-29)m`
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