Plots for 2s orbital are
X, Y and Z respectively.

Options

A. `R,R^(2) and 4pir^(2)R^(2)`
B. `R^(2),R and 4pir^(2)R^(2)`
C. `4pir^(2)R^(2),R^(2) and R`
D. `R^(2),4pir^(2)R^(2) and R`.

Answer

B

Explanation

Y will be definitely 'R' because value of R cannot be negative, thus X will be `R^(2)` and Z will be `4pir^(2)`. Z respresents radial probability function, its value will be zero at origin.