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The Wave function (Psi) of 2s is given b...

The Wave function (Psi) of 2s is given by:
`Psi_(2s)=(1)/(2sqrt2pi)(1/a_(0))^(1//2){2-(r)/a^(0)}e^(-r//2a_(0))`
At `r =r_(0)`, radial node is formed . Thus for 2s `,r_(0),` in terms of `a_(0)` is-

A

`r_(0)=a_(0)`

B

`r_(0)=2a_(0)`

C

`r_(0)=a_(0)//2`

D

`r_(0)=4a_(0)`

Text Solution

Verified by Experts

The correct Answer is:
B

When `r=r_(0),Phi_(2s)=0`, then from the given equation: ltbr. `2-(r)/(a_(0))=0`
`r=2a_(0)`.
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