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The orbital angular momentum of an elect...

The orbital angular momentum of an electron in a d-orbital is:

A

`sqrt(6)(h)/(2pi)`

B

`sqrt(h)/(2pi)`

C

`(h)/2pi`

D

`(2h)/(2pi)`

Text Solution

Verified by Experts

The correct Answer is:
A
Orbital angular momentum `=sqrt(l(l+1))(h)/(2pi)`
`=sqrt(2(2+1))(h)/(2pi)=sqrt(6)(h)/(2pi)`
(here, l=2, for d-orbital)
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