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Let a light of wavelength lamda and inte...

Let a light of wavelength `lamda` and intensity 'I' strikes a metal surface to emit x electrons per second. Average energy of each electron is 'y' unit. What will happen to 'x' and 'y' when (a). `lamda` is halved (b) intensity I is doubled?

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(a). Rate of emission of electron is independent of wavelength. Hence 'x' will be unaffected.
Kinetic energy of photoelectron=Absorbed energy-Threshold energy
`y=(hc)/(lamda)-w_(0)`
When `lamda` is halved, average energy will increase but it will not become double.
(b). Rate of emission of electron per second 'x' will become double when intensity I is doubled. Average energy of ejected.
Electron i.e., 'y' will be unaffected by increase in the intensity of light.
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