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The binding energy of .(2)^(4)He is 28.5...

The binding energy of `._(2)^(4)He` is 28.57 MeV.
What shall be the binding energy per nucleon of this element?

Text Solution

Verified by Experts

The nucleus of `._(2)^(4)He` consists of 4 nucleons.
So, Binding energy per nucleon `=("Total binding energy")/("No. of nucleons")`
`=(28.57)/(4)=7.14MeV`
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