Calculate the binding energy of the oxygen isotope `._(8)^(16)O`. The mass of the isotope is 16.0 amu. (Given e=0.0005486 amu, p=1.00757 amu and n=1.00893 amu).

Explanation

The isotope `._(8)^(16)O` contains 8 protons,
8 neutrons and 8 electrons.
Actual mass of the nucleus of `._(8)^(16)O`
`=16-`mass of 8 electrons
`=16-8xx0.0005486=15.9956`amu
Mass of the nucleus of `._(8)^(16)O`
=Mass of 8 protons + Mass of 8 neutrons
`=8xx1.00757+8xx1.00893=16.132`amu
Mass defect `=(16.132-15.9956)=0.1364` amu
Binding energy `=0.1364xx931=127`MeV