Hydrogen atoms are excited from ground state. Its spectrum contains wavelength 486 nm. Find , what transition does the line corresponds to. Also find from this information what other wavelengths will be present in the spectrum?

Explanation

Wavelength 486 nm, i.e., 4860Ã… indicates that the spectrum is in visible region, i.e., Balmer series.
`(1)/(lamda)=RZ^(2)[(1)/(n_(1)^(2))-(1)/(n_(2)^(2))]`
`(1)/(4860xx10^(-8))=109677.76xx1^(2)[(1)/(2^(2))-(1)/(n_(2)^(2))]`
On, solving, we get,
`n_(2)^(2)=16`
`n_(2)=4`
Thus, transition is from `4to2`
Other transition int he spectrum are
`4to3to2`
`(1)/(lamda)=109677.76xx1^(2)xx[(1)/(3^(2))-(1)/(4^(2))]`
`lamda=1875xx10^(-7)cm`.