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The angular momentum of electron in a ...

The angular momentum of electron in a Bohr's orbit of H atom is `4.2178 xx 10^(-34) kg m^(2)s^(-1)`. Calculate the wavelength of the spectral line when the electrton falls from this level to the next lower level.

Text Solution

Verified by Experts

We know, `mvr=n(h)/(2pi)`
`4.2178xx10^(-34)=nxx(6.626xx10^(-34))/(2xx3.14)`
`thereforen=4`
`(1)/(lamda)=R_(H)[(1)/(n_(1)^(2))-(1)/(n_(2)^(2))]`
`=109678[(1)/(3^(2))-(1)/(4^(2))]`
`lamda=1.8xx10^(-4)cm`
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