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The energy of an alpha-particle is 6.8xx...

The energy of an `alpha`-particle is `6.8xx10^(-18)J`. What will be the wavelength associated with it?

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The correct Answer is:
`lamda=(h)/(sqrt(2Em))=(6.626xx10^(-34))/(sqrt(2xx6.8xx10^(-18)xx4xx1.66xx10^(-27)))`
`=2.2xx10^(-12)`m
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