The wavelength of the first member of the balmer series of hydrogen is `6563xx10^(-10)m`. Calculate the wavelength of its second member.

Explanation

`(1)/(lamda_(1))=R_(H)[(1)/(2^(2))-(1)/(3^(2))] and (1)/(lamda_(2))=R_(H)[(1)/(2^(2))-(1)/(4^(2))]`
`(lamda_(2))/(lamda_(1))=(5)/(36)xx(16)/(3)=(20)/(27)`
`lamda_(2)=(20)/(27)xx6563xx10^(-10)=4861xx10^(-10)m`.