What hydrogen-like ion has the wavelength difference between the first lines of the Balmer Lyman series equal to `59.3nm`?

Explanation

Wavelength of 1st line in Balmer series.
`(1)/(lamda_(B))=Z^(2)R_(H)[(1)/(2^(2))-(1)/(3^(2))]=(5)/(36)R_(H)Z^(2)`
or `lamda_(B)=(36)/(5R_(H)Z^(2))`
Wavelength of 1 st line in lyman series is,
`(1)/(lamda_(L))=Z^(2)R_(B)[(1)/(1^(2))-(1)/(2^(2))]`
or `lamda_(L)=(4)/(3xxR_(H)Z^(2))`
Difference `lamda_(B)-lamda_(L)=59.3xx10^(-7)=(36)/(5R_(H)Z^(2))-(4)/(3R_(H)Z^(2))`
`=(1)/(R_(H)Z^(2))[(36)/(5)-(4)/(3)]`
`Z^(2)=(88)/(59.3xx10^(-7)xx109678xx15)=9.0`
or `Z=3`
Hydrogen-like species is `Li^(2+)`.