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A 1 MeV proton is sent against a gold le...

A 1 MeV proton is sent against a gold leaf `(Z=79)`. Calculate the distance of closest approach for head-on collision.

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Verified by Experts

The correct Answer is:
`1.137xx10^(-13)m`
`d=(Ze^(2))/(4piepsi_(0)(1//2 mv^(2)))`.
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