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A single electron system has ionization ...

A single electron system has ionization energy 11180 kJ `mol^(-1)`. Find the number of protons in the nucleus of the system.

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Verified by Experts

The correct Answer is:
Z=3
`IE=(Z^(2))/(n^(2))xx21.69xx10^(-19)J`
`(11180xx10^(3))/(6.023xx10^(23))=(Z^(2))/(1^(2))xx21.69xx10^(-19)`
`Z~~3`.
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