From the electronic configuration of the given elements K,L, M and N, which one has the highest ionization potential?

Options

A. `M=[Ne]3s^(2)3p^(2)`
B. `L=[Ne]3s^(2)3p^(3)`
C. `K=[Ne]3s^(2)3p^(1)`
D. `N=[Ar]3d^(10),4s^(2)4p^(3)`

Answer

B

Explanation

L has half-filled p-subshell and it is smaller than N, hence, L will have the highest ionization potential.