The total energy of the electron of H-atom in the second quantum state is `-E_(2)`. The total energy of the `He^(+)` atom in the third quantum state is:

Options

A. `-((3)/(2))E_(2)`
B. `-((2)/(3))E_(2)`
C. `-((4)/(9))E_(2)`
D. `-((16)/(9))E_(2)`

Answer

C

Explanation

Energy of electrons in n th state
`=-(Z^(2))/(n^(2))xx13.6eV`
`E_(2)(H)=-(13.6)/(1)eV`
`E_(3)(He^(+))=-(13.6xx4)/(9)eV`
`(E_(2))/(E_(3))=(9)/(4)" or "E_(3)=(4)/(9)E_(2)`.
For negative value of `E_(2),E_(3)` will also be negative.