If the kinetic energy of a particle is doubled, de Broglie wavelength becomes:

Options

A. 2 times
B. 4 times
C. `sqrt(2)`times
D. `(1)/(sqrt(2))` times

Answer

D

Explanation

`lamda=(h)/(sqrt(2Em))` where E=Kinetic energy of the particle
`thereforelamda_(1)=(h)/(sqrt(2Em)),lamda_(2)=(h)/(sqrt(2xx2Em))`
`(lamda_(1))/(lamda_(2))=sqrt(2)` i.e., `lamda_(2)=(lamda_(1))/(sqrt(2))`