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An excited state of H atom emits a photo...

An excited state of H atom emits a photon of wavelength `lamda` and returns in the ground state. The principal quantum number of excited state is given by:

A

`sqrt(lamdaR(lamdaR-1))`

B

`sqrt((lamdaR)/((lamdaR-1)))`

C

`(1)/(sqrt(lamdaR(lamdaR-1)))`

D

`sqrt(((lamdaR-1))/(lamdaR))`

Text Solution

Verified by Experts

The correct Answer is:
B

`(1)/(lamda)=R[(1)/(n_(1)^(2))-(1)/(n_(2)^(2))]=R[(1)/(1)-(1)/(n_(2)^(2))]`
`n_(2)=sqrt((lamda)/(lamdaR-1))`
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