Not considering the electronic spin, the degeneracy of the second excited state `(n = 3)` of H-atom is 9, while the degeneracy of the second excited state of `H^(-)` is

Answer

3

Explanation

`H^(-)` is a multielectron species. Hence, it will follow `(n+l)`
rule `H^(-)(2e)to1s^(2)2s^(0)2p^(0)` (gound state)
`to1s^(2)2s2p^(1)` (second excited state)
Degeneracy=3