A sample of a gas occupies 600 mL at `27^(@)C` and 1 atm. What will be the volume at `127^(@)C` if the pressure is kept constant ?

Explanation

`V_(1) = 600 mL T_(1) = 27 + 273 = 300 K`
`V_(2) = ? T_(2) = 127 + 273 = 400 K`
Applying Charles' law, `(V_(1))/(T_(1)) = (V_(2))/(T_(2))`
`V_(2) = (V_(1))/(T_(1)) xx T_(2) = (600 xx 400)/(300) = 800 mL`