A gas cylinder containing cooking gas can withsand a pressure of 14.9 atmosphere. The pressure gauge of the cylinder indicates 12 atmosphere at `27^(@)C`. Due to a sudden fire in the building the temperature starts rising. At what temperature will the cylinder explode ?

Explanation

Since, the gas is confined in a cylinder, its volume will remain constant
`{:("Initial conditions","Final conditions",),(P_(1) = 12 atm,P_(2) = 14.9 atm,),(T_(1) = 27 + 273 = 300 K,T_(2) = ?,):}`
Applying pressure - temperature law,
`(P_(1))/(T_(1)) = (P_(2))/(T_(2))`
So, `T_(2) = (P_(2) xx T_(1))/(P_(1)) = (14.9 xx 300)/(12) = 372.5 K`
Temperature in `.^(@)C = (372.5 - 273) = 99.5^(@)C`