A sample of a gas occupies a volume of 512 mL at `20^(@)C` and `74 cm` of Hg as pressure. What volume would this gas occupy at STP ?

Explanation

`{:("Initial conditions","Final conditions" (STP),),(P_(1) = 74 cm,P_(2) = 76 cm,),(T_(1) = 20^(@)C = (20 + 273) = 293 K,T_(2) = 0^(@)C = 273 K,),(V_(1) = 512 mL,V_(2) = ?,):}`
We know that, `(P_(1)V_(1))/(T_(1)) = (P_(2) V_(2))/(T_(2))`
`(74 xx 512)/(293) = (76 xx V_(2))/(273)`
So, `V_(2) = (74 xx 512 xx 273)/(293 xx 76)`
`= 464.5 mL`