Calculate the value of molar gas contant, 'R' in (i) cc atm `K^(-1) mol^(-1)` (ii) torr `cc K^(-1) mol^(-1)` (ii) `kPa` litre `K^(-1) mol^(-1)`

Explanation

(i) When the pressure is expressed in atmosphere and volume in `cc`.
`P = 1 atm, V = 22400 cc`
`R = (PV)/(nT) = (1 xx 22400)/(1 xx 273) = 82.1 cc atm K^(-1) mol^(-1)`
(ii) When the pressure is expressed in torr and volume in `cc`.
`P = 760 " torr ", V = 22400 cc`
`R = (760 xx 22400)/(1 xx 273) = 62360 " torr " cc K^(-1) mol^(-1)`
(iii) When the pressure is expressed in `k` Pascal and volume in litre.
`P = 101.3 kPa, V = 22.4`litre
`R = (PV)/(nT) = (101.3 xx 22.4)/(1 xx 273) = 8.31 k Pa " litre " K^(-1) mol^(-1)`