The pressure exerted by `12 g` of an ideal gas at temperature `t^(@)C` in a vessel of volume `V litre` is `1 atm`. When the temperature is increased by `10^(@)C` at the same volume, the pressure increases by `10%`. Calculate the temperature `t` and volume `V`. (Molecular weight of the gas is `120`).

Explanation

As the volume is constant, pressure law can be applied, i.e.,
`(P_(1))/(P_(2)) = (T_(1))/(T_(2))`
or `(1)/(1.1) = (t + 273)/(t + 283)`
or `t = - 173^(@)C = 100 K`
Now, applying gas equation,
`PV = nRT`
or `V = (n)/(P) RT = (12 xx 0.082 xx 100)/(120 xx 1) = 0.82` litre