20 `dm^(3)` of `SO_(2)` diffuse through a porous partition in 60 s. what volume of `O_(2)` will diffuse under similar conditions in 30 s ?

Explanation

Rate of diffusion of `SO_(2) = (20)/(60) dm^(3) s^(-1)`
Rate of diffusion of `O_(2) = (V)/(30) dm^(3) s^(-1)`
According to Graham's law of diffusion
`((V//30))/((20//60)) = sqrt((M_(SO_(2)))/(M_(O_(2)))) = sqrt((64)/(32))`
`V = 14.1 dm^(3)`