The ratio of rate of diffusion of gases A and B is `1 : 4`. If the ratio of their masses present in the mixture is `2 : 3`, what is the ratio of their mole fraction ?

Explanation

`(r_(A))/(r_(B)) = sqrt((M_(B))/(M_(A)) = (1)/(4)`
or `(M_(B))/(M_(A)) = (1)/(16)`
Mole fraction of `A =((W_(A))/(M_(A)))/((W_(A))/(M_(A)) + (W_(B))/(M_(B)))`
Mole fraction of `B = ((W_(B))/(M_(B)))/((W_(A))/(M_(A)) + (W_(B))/(M_(B)))`
Ratio `= (W_(A))/(M_(A)) xx (M_(B))/(W_(B))`
or `(W_(A))/(W_(B)) xx (M_(B))/(M_(A)) = (2)/(3) xx (1)/(16) = (1)/(24)`