`100 cm^(3) " of " NH_(3)` diffuses through a pin hole in 32.5 second. How much time will `60 cc " of " N_(2)` take to diffuse under the same conditions ?

Explanation

`(r_(NH_(3)))/(r_(N_(2))) = sqrt((M_(N_(2)))/(M_(NH_(3))))`
`(100 //32.5)/(60//t) = sqrt((28)/(17))`
`(100 xx t)/(60 xx 32.5) = sqrt((28)/(17))`
`t = 25` second