Calculate the average kinetic energy (in joule) per molecule in `8.0 g` of methane at `27^(@)C`.

Explanation

Number of gram moles of methane `= (8)/(16) = (1)/(2)`
`T = (27 + 273) = 300 K`
`R = 8.32 J K^(-1) mol^(-1)`
Kinetic energy for one gram mole `= (3)/(2) RT`
`= (3)/(2) xx 8.32 xx 300 J`
Thus
kinetic energy for `(1)/(2)` gram mole `= (1)/(2) xx (3)/(2) xx 8.32 xx 300`
`= 1872 J`